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-4.9x^2+12.86x=-40
We move all terms to the left:
-4.9x^2+12.86x-(-40)=0
We add all the numbers together, and all the variables
-4.9x^2+12.86x+40=0
a = -4.9; b = 12.86; c = +40;
Δ = b2-4ac
Δ = 12.862-4·(-4.9)·40
Δ = 949.3796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.86)-\sqrt{949.3796}}{2*-4.9}=\frac{-12.86-\sqrt{949.3796}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.86)+\sqrt{949.3796}}{2*-4.9}=\frac{-12.86+\sqrt{949.3796}}{-9.8} $
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